Let Pk is the probability that exactly K attempts are required to transmit a frame.
Pk = ( 1- e-G )k-1 .
( e-G )1
( 1- e-G )k-1 is Probability of
failure
( e-G )1 is Probability of failure
Excepted number of attempt
E = eG
Where: G is load, E is exponential load
NOTE: Number of attempt will reduce if load is less.
FINITE POPULATION ALOHA / SLOTTED ALOHA
There are N number of station are compiling for a single
channel SLOTTED ALOHA channel.
Gi : It is a load shared by the station I, that
means number of frame including new entry transmission transmitted by station
is per frame time) / It is probability that station ( I ) will transmit in a
particular slot.
Si : Throughput shared by a station ( I ), that
means probability that particular station I will transmit successful.
OR
Mean / average number of successful transmission per frame
time by station (i).
Si = Gi (1 – G1) (1 –G2) ---------- (1 – GN)
Let the channel load is G
G = G1 + G2 + G3
+ ----------- + GN
ASSUME :
G = G1 + G2 + G3
+ ----------- + GN
Load shared by all station are equal
than.
G = N . Gi
Gi = G / N
Let the throughput of the channel is
S
S = S1 + S2 + S3
+ ----------- + SN
ASSUME :
S1 = S2+ S2
+ S3 + ----------- + SN
Si = S /N
than
Put Si = S/N , Gi = G/N
S/N = G/N (
1 - G/N )N-1
S = G ( 1 - G/N )N-1
For infinite population ALOHA /
Infinite slotted ALOHA
If N = infinite
S = G . e-G
For what value of G , S will be maximum.
If
G = 1 than
S will be maximum.
QUESTION: Consider the delay of PURE ALOHA and SLOTTED ALOHA.
ANSWER: We can measure ALOHA by two parameters.
1. Delay
2. Throughput / Efficiency / Utilisation
Delay can be compared in the case of extreme load due to some rules. Such as only one
can be transmitted.
In PURE ALOHA delay = 0 , because when any sander make their message immediately
they can able to send the message without waiting at time slot.
In SLOTTED ALOHA we have to wait for one time slot. This delay is due to rules
( such as only one can be transmit / we cannot transmit until previous are not completed)
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