Find the DepartNo and Department name for each employee.

For solving the above question we need to create two tables (EMPLOYEE , DEPARTMENT)

create table employee
(
empid number(5) primary key,
empname varchar2(50),
salary number(10,2),
Grade number(1),
deptno number(3) references department(deptno),
location varchar2(50),
desig varchar(20)
);

create table department
(
deptno number(3) primary key,
deptname varchar(50)
);

Then Insert few records in Employee and Department table.

EMPLOYEE

EMPID	EMPNAME	SALARY	GRADE	DEPTNO	LOCATION	DESIG
1	AMIT SEN	10000	1	1	BHOPAL	MANAGER
2	RAMESH THAKUR	11000	2	1	BHOPAL	CLERK
3	RAKESH	12000	1	1	INDORE	CLERK
4	SUMIT SAKET	9000	3	2	BHOPAL	CLERK
5	AMIT SEN	11000	2	2	BHOPAL	MANAGER
6	AMIT SEN	12000	2	5	INDORE	CLERK
7	AMIT SEN	15000	1	6	INDORE	MANAGER

DEPARTMENT

DEPTNO	DEPTNAME
1	SALES
2	PRODUCTION
3	PURCHASE
4	MARKETING
5	ACCOUNTS
6	HR
7	ADMIN

SQL :
select e.empname, d.deptno, d.deptname from department d , employee e where d.deptno=e.deptno;

RESULT :

EMPNAME	DEPTNO	DEPTNAME
AMIT SEN	1	SALES
RAMESH THAKUR	1	SALES
RAKESH	1	SALES
SUMIT SAKET	2	PRODUCTION
AMIT SEN	2	PRODUCTION
AMIT SEN	5	ACCOUNTS
AMIT SEN	6	HR